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2010-12-21
, 10:38
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Posts: 306 |
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Joined on Jan 2010
@ Romania
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#32
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2400 mAh per day = 0.1A per hour times 3,7 V = 0.37 W per hour
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2010-12-21
, 11:06
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Posts: 1,341 |
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Joined on Feb 2010
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#33
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2010-12-21
, 12:55
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Posts: 113 |
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Joined on Jan 2010
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#34
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2010-12-21
, 12:56
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Posts: 752 |
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Joined on Sep 2010
@ Malaysia
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#35
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2010-12-21
, 13:06
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Posts: 113 |
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Joined on Jan 2010
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#36
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2010-12-21
, 13:08
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Posts: 1,341 |
Thanked: 708 times |
Joined on Feb 2010
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#37
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The battery should have a total energy of 8.88Wh=8.88Jh/s=8.88J*3600s/s=32kJ...
Actually 0.37 W per every second, don't you think?
2400 mAh / 24h * 3.7V = 0.37 VA = 0.37 W
Which would mean the battery is drained 100 mA in average constantly.
(Check: 100mA * 24 h * 60 * 60 / (60 * 60) = 2400 mAh)
The worst case scenario; all that energy would be radiated out in 500 - 3000 Mhz area (GSM,UMTS,BT,WLAN). The maximum output power is limited to 2W, so daily it would radiate 4h 26min @ 2W.
Continuing the worst case scenario, all that 32 kJ radiation daily would be absorbed by my tissues. Should I worry?
(The worse than the worst case scenario:
If all that energy (32 kJ - one day) would be converted to X-rays, I (90kg) would get about 355 Gy, which would kill me.)
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2010-12-21
, 13:22
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Posts: 752 |
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Joined on Sep 2010
@ Malaysia
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#38
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This is the wrong question. A beer has something about 200kJ, but the beer's energy is not absorbed by your body as it happens with the energy of the phones EM-radiation.U rather wanna know how warm the tissue around your ear will become as this or parts of this energy are absorbed while using ur phone. This could than be used as a measure of how dangerous it would be to use ur phone.
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2010-12-21
, 13:43
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Posts: 1,258 |
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Joined on Mar 2009
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#39
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2010-12-21
, 14:00
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Posts: 752 |
Thanked: 284 times |
Joined on Sep 2010
@ Malaysia
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#40
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Last edited by stone17; 2010-12-20 at 23:23.